{"id":5471,"date":"2026-10-26T18:03:32","date_gmt":"2026-10-26T12:33:32","guid":{"rendered":"https:\/\/johnsonfrancis.org\/horticulture\/?p=5471"},"modified":"2026-10-26T18:03:34","modified_gmt":"2026-10-26T12:33:34","slug":"electricity-and-magnetism-mcqs","status":"publish","type":"post","link":"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/","title":{"rendered":"Electricity and Magnetism MCQs"},"content":{"rendered":"\n
\n

Physics: Electricity & Magnetism MCQs<\/h2>\n\n \n
\n

1. If the distance between two equal point charges is doubled, the electrostatic force between them becomes:<\/strong><\/p>\n

    \n
  • A) Half of the original force<\/li>\n
  • B) Double the original force<\/li>\n
  • C) One-fourth of the original force<\/li>\n
  • D) Four times the original force<\/li>\n <\/ul>\n
    \n View Answer & Explanation<\/summary>\n

    Answer: C<\/strong>
    Explanation: According to Coulomb’s Law, F \u221d 1\/r\u00b2. If r is doubled, the new force becomes F\/(2)\u00b2 = F\/4.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

    \n

    2. The electric field intensity inside a hollow charged spherical conductor is:<\/strong><\/p>\n

      \n
    • A) Infinite<\/li>\n
    • B) Zero<\/li>\n
    • C) Uniform but non-zero<\/li>\n
    • D) Dependent on the radius of the sphere<\/li>\n <\/ul>\n
      \n View Answer & Explanation<\/summary>\n

      Answer: B<\/strong>
      Explanation: Charges reside only on the outer surface of a conductor. Therefore, by Gauss’s Law, the net charge inside is zero, making the electric field zero.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

      \n

      3. The work done in moving a charge of 5 Coulombs from one point to another on an equipotential surface is:<\/strong><\/p>\n

        \n
      • A) 5 Joules<\/li>\n
      • B) 25 Joules<\/li>\n
      • C) Zero<\/li>\n
      • D) Infinite<\/li>\n <\/ul>\n
        \n View Answer & Explanation<\/summary>\n

        Answer: C<\/strong>
        Explanation: On an equipotential surface, the potential difference (\u0394V) between any two points is zero. Work done W = q(\u0394V) = 0.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

        \n

        4. Three capacitors of capacitances 2 \u00b5F, 3 \u00b5F, and 6 \u00b5F are connected in series. The equivalent capacitance is:<\/strong><\/p>\n

          \n
        • A) 11 \u00b5F<\/li>\n
        • B) 1 \u00b5F<\/li>\n
        • C) 1.2 \u00b5F<\/li>\n
        • D) 36 \u00b5F<\/li>\n <\/ul>\n
          \n View Answer & Explanation<\/summary>\n

          Answer: B<\/strong>
          Explanation: For capacitors in series: 1\/Cs = 1\/C1 + 1\/C2 + 1\/C3. Therefore, 1\/Cs = 1\/2 + 1\/3 + 1\/6 = 3\/6 + 2\/6 + 1\/6 = 6\/6 = 1. Cs = 1 \u00b5F.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

          \n

          5. If a uniform wire of resistance R is stretched to double its original length, its new resistance will be:<\/strong><\/p>\n

            \n
          • A) R<\/li>\n
          • B) 2R<\/li>\n
          • C) 4R<\/li>\n
          • D) R\/2<\/li>\n <\/ul>\n
            \n View Answer & Explanation<\/summary>\n

            Answer: C<\/strong>
            Explanation: Volume remains constant. If length is doubled (l’ = 2l), area becomes half (A’ = A\/2). Resistance R = \u03c1(l\/A). New resistance R’ = \u03c1(2l \/ (A\/2)) = 4 \u03c1(l\/A) = 4R.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

            \n

            6. Kirchhoff’s First Law (Junction Rule) is a consequence of the conservation of:<\/strong><\/p>\n

              \n
            • A) Energy<\/li>\n
            • B) Momentum<\/li>\n
            • C) Charge<\/li>\n
            • D) Mass<\/li>\n <\/ul>\n
              \n View Answer & Explanation<\/summary>\n

              Answer: C<\/strong>
              Explanation: The junction rule states that total current entering a junction equals the total current leaving it, which is the principle of conservation of electric charge.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

              \n

              7. The drift velocity of free electrons in a conductor is directly proportional to:<\/strong><\/p>\n

                \n
              • A) The square of the electric field<\/li>\n
              • B) The applied electric field<\/li>\n
              • C) The volume of the conductor<\/li>\n
              • D) The reciprocal of the electric field<\/li>\n <\/ul>\n
                \n View Answer & Explanation<\/summary>\n

                Answer: B<\/strong>
                Explanation: Drift velocity (Vd) = (eE\/m)\u03c4, where E is the applied electric field. Thus, Vd \u221d E.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                \n

                8. An ideal voltmeter should have:<\/strong><\/p>\n

                  \n
                • A) Zero resistance<\/li>\n
                • B) Very low resistance<\/li>\n
                • C) Very high but finite resistance<\/li>\n
                • D) Infinite resistance<\/li>\n <\/ul>\n
                  \n View Answer & Explanation<\/summary>\n

                  Answer: D<\/strong>
                  Explanation: An ideal voltmeter draws no current from the circuit so it does not alter the potential difference it is measuring. Therefore, it must have infinite resistance.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                  \n

                  9. A charged particle moves parallel to a uniform magnetic field. The magnetic force on the particle is:<\/strong><\/p>\n

                    \n
                  • A) Maximum<\/li>\n
                  • B) Zero<\/li>\n
                  • C) Dependent on the particle’s mass<\/li>\n
                  • D) Circular<\/li>\n <\/ul>\n
                    \n View Answer & Explanation<\/summary>\n

                    Answer: B<\/strong>
                    Explanation: Magnetic force F = qvB sin(\u03b8). If the particle moves parallel to the field, \u03b8 = 0\u00b0, so sin(0\u00b0) = 0, and the force is zero.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                    \n

                    10. The path of a charged particle entering a uniform magnetic field at a right angle is:<\/strong><\/p>\n

                      \n
                    • A) Straight line<\/li>\n
                    • B) Parabola<\/li>\n
                    • C) Circle<\/li>\n
                    • D) Helix<\/li>\n <\/ul>\n
                      \n View Answer & Explanation<\/summary>\n

                      Answer: C<\/strong>
                      Explanation: When velocity is perpendicular to the magnetic field, the magnetic force acts as a centripetal force, causing the particle to move in a circular path.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                      \n

                      11. How can a galvanometer be converted into an ammeter?<\/strong><\/p>\n

                        \n
                      • A) By connecting a high resistance in series<\/li>\n
                      • B) By connecting a high resistance in parallel<\/li>\n
                      • C) By connecting a low resistance in series<\/li>\n
                      • D) By connecting a low resistance in parallel<\/li>\n <\/ul>\n
                        \n View Answer & Explanation<\/summary>\n

                        Answer: D<\/strong>
                        Explanation: A low resistance (shunt) connected in parallel allows most of the current to bypass the galvanometer, thereby increasing its measuring range and converting it into an ammeter.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                        \n

                        12. The magnetic susceptibility of a diamagnetic substance is:<\/strong><\/p>\n

                          \n
                        • A) Small and positive<\/li>\n
                        • B) Large and positive<\/li>\n
                        • C) Small and negative<\/li>\n
                        • D) Zero<\/li>\n <\/ul>\n
                          \n View Answer & Explanation<\/summary>\n

                          Answer: C<\/strong>
                          Explanation: Diamagnetic materials create an induced magnetic field in a direction opposite to an externally applied magnetic field, resulting in a small, negative magnetic susceptibility.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                          \n

                          13. What is the value of the angle of dip at the Earth’s magnetic poles?<\/strong><\/p>\n

                            \n
                          • A) 0\u00b0<\/li>\n
                          • B) 45\u00b0<\/li>\n
                          • C) 90\u00b0<\/li>\n
                          • D) 180\u00b0<\/li>\n <\/ul>\n
                            \n View Answer & Explanation<\/summary>\n

                            Answer: C<\/strong>
                            Explanation: At the magnetic poles, the Earth’s magnetic field lines point vertically downwards or upwards, making an angle of 90\u00b0 with the horizontal.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                            \n

                            14. Lenz’s Law of electromagnetic induction strictly adheres to the principle of conservation of:<\/strong><\/p>\n

                              \n
                            • A) Charge<\/li>\n
                            • B) Mass<\/li>\n
                            • C) Momentum<\/li>\n
                            • D) Energy<\/li>\n <\/ul>\n
                              \n View Answer & Explanation<\/summary>\n

                              Answer: D<\/strong>
                              Explanation: Lenz’s Law states the induced current opposes the change in magnetic flux. The mechanical work done against this opposing force is converted into electrical energy, conserving total energy.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                              \n

                              15. The core of a transformer is laminated to reduce energy losses due to:<\/strong><\/p>\n

                                \n
                              • A) Flux leakage<\/li>\n
                              • B) Copper loss<\/li>\n
                              • C) Eddy currents<\/li>\n
                              • D) Hysteresis<\/li>\n <\/ul>\n
                                \n View Answer & Explanation<\/summary>\n

                                Answer: C<\/strong>
                                Explanation: Laminating the core breaks the conducting path, significantly increasing electrical resistance and thereby reducing the magnitude of eddy currents and the resulting heat loss.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                \n

                                16. The SI unit of magnetic flux is the:<\/strong><\/p>\n

                                  \n
                                • A) Tesla<\/li>\n
                                • B) Weber<\/li>\n
                                • C) Henry<\/li>\n
                                • D) Gauss<\/li>\n <\/ul>\n
                                  \n View Answer & Explanation<\/summary>\n

                                  Answer: B<\/strong>
                                  Explanation: Tesla is the unit of magnetic field strength (B), while Weber (Wb) is the unit of magnetic flux (\u03a6).<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                  \n

                                  17. The power factor of a purely inductive AC circuit is:<\/strong><\/p>\n

                                    \n
                                  • A) 1<\/li>\n
                                  • B) 0.5<\/li>\n
                                  • C) 0<\/li>\n
                                  • D) Infinite<\/li>\n <\/ul>\n
                                    \n View Answer & Explanation<\/summary>\n

                                    Answer: C<\/strong>
                                    Explanation: In a purely inductive circuit, the phase difference (\u03c6) between voltage and current is 90\u00b0 (\u03c0\/2). The power factor is cos(\u03c6) = cos(90\u00b0) = 0.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                    \n

                                    18. At resonance in an LCR series circuit, the phase difference between voltage and current is:<\/strong><\/p>\n

                                      \n
                                    • A) \u03c0\/2<\/li>\n
                                    • B) \u03c0<\/li>\n
                                    • C) \u03c0\/4<\/li>\n
                                    • D) 0<\/li>\n <\/ul>\n
                                      \n View Answer & Explanation<\/summary>\n

                                      Answer: D<\/strong>
                                      Explanation: At resonance, inductive reactance equals capacitive reactance (Xl = Xc). The circuit behaves as a purely resistive circuit, meaning voltage and current are in phase (angle = 0).<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                      \n

                                      19. Electromagnetic waves are produced by:<\/strong><\/p>\n

                                        \n
                                      • A) Static charges<\/li>\n
                                      • B) Charges in uniform motion<\/li>\n
                                      • C) Accelerating charges<\/li>\n
                                      • D) Uncharged particles<\/li>\n <\/ul>\n
                                        \n View Answer & Explanation<\/summary>\n

                                        Answer: C<\/strong>
                                        Explanation: A static charge produces only an electric field. A charge in uniform motion produces both electric and magnetic fields but no waves. Accelerating charges emit electromagnetic radiation.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                        \n

                                        20. The magnetic field at the center of a circular current-carrying coil of radius R and current I is given by:<\/strong><\/p>\n

                                          \n
                                        • A) \u03bc\u2080I \/ 2\u03c0R<\/li>\n
                                        • B) \u03bc\u2080I \/ 2R<\/li>\n
                                        • C) \u03bc\u2080I \/ 4\u03c0R<\/li>\n
                                        • D) \u03bc\u2080I \/ R<\/li>\n <\/ul>\n
                                          \n View Answer & Explanation<\/summary>\n

                                          Answer: B<\/strong>
                                          Explanation: According to the Biot-Savart law, the magnetic field at the center of a single circular loop is B = \u03bc\u2080I \/ 2R. (\u03bc\u2080I \/ 2\u03c0R is for a straight infinite wire).<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                          \n

                                          21. In a purely capacitive AC circuit, the relationship between current and voltage is:<\/strong><\/p>\n

                                            \n
                                          • A) Current lags voltage by \u03c0\/2<\/li>\n
                                          • B) Current leads voltage by \u03c0\/2<\/li>\n
                                          • C) Current and voltage are in phase<\/li>\n
                                          • D) Current leads voltage by \u03c0<\/li>\n <\/ul>\n
                                            \n View Answer & Explanation<\/summary>\n

                                            Answer: B<\/strong>
                                            Explanation: In a capacitor, current leads the voltage by a phase angle of 90 degrees (\u03c0\/2 radians). ICE is a helpful mnemonic (Current ‘I’ leads Voltage ‘E’ in a Capacitor ‘C’).<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                            \n

                                            22. The Biot-Savart Law in magnetism plays a role analogous to which law in electrostatics?<\/strong><\/p>\n

                                              \n
                                            • A) Gauss’s Law<\/li>\n
                                            • B) Faraday’s Law<\/li>\n
                                            • C) Coulomb’s Law<\/li>\n
                                            • D) Ampere’s Law<\/li>\n <\/ul>\n
                                              \n View Answer & Explanation<\/summary>\n

                                              Answer: C<\/strong>
                                              Explanation: Coulomb’s law calculates the electric field produced by an infinitesimal charge element, whereas the Biot-Savart law calculates the magnetic field produced by an infinitesimal current element.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                              \n

                                              23. Which of the following electromagnetic waves has the highest frequency?<\/strong><\/p>\n

                                                \n
                                              • A) X-rays<\/li>\n
                                              • B) Ultraviolet rays<\/li>\n
                                              • C) Gamma rays<\/li>\n
                                              • D) Microwaves<\/li>\n <\/ul>\n
                                                \n View Answer & Explanation<\/summary>\n

                                                Answer: C<\/strong>
                                                Explanation: On the electromagnetic spectrum, Gamma rays possess the shortest wavelength and thus the highest frequency and highest energy.<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                                \n

                                                24. The cyclotron frequency of a charged particle moving in a magnetic field is independent of its:<\/strong><\/p>\n

                                                  \n
                                                • A) Mass<\/li>\n
                                                • B) Charge<\/li>\n
                                                • C) Speed<\/li>\n
                                                • D) Magnetic field strength<\/li>\n <\/ul>\n
                                                  \n View Answer & Explanation<\/summary>\n

                                                  Answer: C<\/strong>
                                                  Explanation: The cyclotron frequency is f = qB \/ (2\u03c0m). It depends on charge, magnetic field, and mass, but is completely independent of the particle’s speed (or radius of its path).<\/em><\/p>\n <\/details>\n <\/div>\n\n \n

                                                  \n

                                                  25. In an AC circuit, the average power dissipated over a complete cycle is given by:<\/strong><\/p>\n

                                                    \n
                                                  • A) V_rms * I_rms<\/li>\n
                                                  • B) V_rms * I_rms * sin(\u03c6)<\/li>\n
                                                  • C) V_rms * I_rms * cos(\u03c6)<\/li>\n
                                                  • D) Zero<\/li>\n <\/ul>\n
                                                    \n View Answer & Explanation<\/summary>\n

                                                    Answer: C<\/strong>
                                                    Explanation: True power in an AC circuit is given by P = V_rms * I_rms * cos(\u03c6), where cos(\u03c6) is known as the power factor.<\/em><\/p>\n <\/details>\n <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

                                                    Physics: Electricity & Magnetism MCQs 1. If the distance between two equal point charges is doubled, the electrostatic force between them becomes: A) Half of the original force B) Double the original force C) One-fourth of the original force D) Four times the original force View Answer & Explanation Answer: CExplanation: According to Coulomb’s Law, […]<\/p>\n","protected":false},"author":1,"featured_media":5473,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"class_list":["post-5471","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-vegetables-at-home"],"yoast_head":"\nElectricity and Magnetism MCQs - Johnson's TechNAgro<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Electricity and Magnetism MCQs - Johnson's TechNAgro\" \/>\n<meta property=\"og:description\" content=\"Physics: Electricity & Magnetism MCQs 1. If the distance between two equal point charges is doubled, the electrostatic force between them becomes: A) Half of the original force B) Double the original force C) One-fourth of the original force D) Four times the original force View Answer & Explanation Answer: CExplanation: According to Coulomb’s Law, […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\" \/>\n<meta property=\"og:site_name\" content=\"Johnson's TechNAgro\" \/>\n<meta property=\"article:published_time\" content=\"2026-10-26T12:33:32+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2026-10-26T12:33:34+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/johnsonfrancis.org\/horticulture\/wp-content\/uploads\/2026\/10\/Medical-Engineering-Entrance-Preparation-Questions-on-Electricity-and-Magnetism.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1208\" \/>\n\t<meta property=\"og:image:height\" content=\"675\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Johnson Francis\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Johnson Francis\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"7 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\"},\"author\":{\"name\":\"Johnson Francis\",\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/#\/schema\/person\/c3636df643ae569b05229e17c67a85f1\"},\"headline\":\"Electricity and Magnetism MCQs\",\"datePublished\":\"2026-10-26T12:33:32+00:00\",\"dateModified\":\"2026-10-26T12:33:34+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\"},\"wordCount\":1390,\"publisher\":{\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/#\/schema\/person\/c3636df643ae569b05229e17c67a85f1\"},\"image\":{\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/johnsonfrancis.org\/horticulture\/wp-content\/uploads\/2026\/10\/Medical-Engineering-Entrance-Preparation-Questions-on-Electricity-and-Magnetism.jpg\",\"articleSection\":[\"Vegetables at home\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\",\"url\":\"https:\/\/johnsonfrancis.org\/horticulture\/electricity-and-magnetism-mcqs\/\",\"name\":\"Electricity and Magnetism MCQs - 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